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134201424211 = 250267536233
BaseRepresentation
bin111110011111100000…
…1110011100101010011
3110211101201122201010221
41330333001303211103
54144321031033321
6141352402133511
712460431166351
oct1747701634523
9424351581127
10134201424211
1151a07229348
1222013951297
13c86945b86a
1466d14927d1
153756b24e41
hex1f3f073953

134201424211 has 4 divisors (see below), whose sum is σ = 134202210712. Its totient is φ = 134200637712.

The previous prime is 134201424209. The next prime is 134201424239. The reversal of 134201424211 is 112424102431.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 134201424211 - 21 = 134201424209 is a prime.

It is a super-3 number, since 3×1342014242113 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134201424241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17850 + ... + 518383.

It is an arithmetic number, because the mean of its divisors is an integer number (33550552678).

Almost surely, 2134201424211 is an apocalyptic number.

134201424211 is a deficient number, since it is larger than the sum of its proper divisors (786501).

134201424211 is an equidigital number, since it uses as much as digits as its factorization.

134201424211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 786500.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 134201424211 its reverse (112424102431), we get a palindrome (246625526642).

The spelling of 134201424211 in words is "one hundred thirty-four billion, two hundred one million, four hundred twenty-four thousand, two hundred eleven".

Divisors: 1 250267 536233 134201424211