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134201424239 is a prime number
BaseRepresentation
bin111110011111100000…
…1110011100101101111
3110211101201122201011222
41330333001303211233
54144321031033424
6141352402133555
712460431166421
oct1747701634557
9424351581158
10134201424239
1151a07229373
12220139512bb
13c86945b88c
1466d1492811
153756b24e5e
hex1f3f07396f

134201424239 has 2 divisors, whose sum is σ = 134201424240. Its totient is φ = 134201424238.

The previous prime is 134201424209. The next prime is 134201424241. The reversal of 134201424239 is 932424102431.

It is a strong prime.

It is an emirp because it is prime and its reverse (932424102431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134201424239 - 216 = 134201358703 is a prime.

Together with 134201424241, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 134201424199 and 134201424208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134201424209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67100712119 + 67100712120.

It is an arithmetic number, because the mean of its divisors is an integer number (67100712120).

Almost surely, 2134201424239 is an apocalyptic number.

134201424239 is a deficient number, since it is larger than the sum of its proper divisors (1).

134201424239 is an equidigital number, since it uses as much as digits as its factorization.

134201424239 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 35.

The spelling of 134201424239 in words is "one hundred thirty-four billion, two hundred one million, four hundred twenty-four thousand, two hundred thirty-nine".