Base | Representation |
---|---|
bin | 111110011111100000… |
… | …1110011100101101111 |
3 | 110211101201122201011222 |
4 | 1330333001303211233 |
5 | 4144321031033424 |
6 | 141352402133555 |
7 | 12460431166421 |
oct | 1747701634557 |
9 | 424351581158 |
10 | 134201424239 |
11 | 51a07229373 |
12 | 220139512bb |
13 | c86945b88c |
14 | 66d1492811 |
15 | 3756b24e5e |
hex | 1f3f07396f |
134201424239 has 2 divisors, whose sum is σ = 134201424240. Its totient is φ = 134201424238.
The previous prime is 134201424209. The next prime is 134201424241. The reversal of 134201424239 is 932424102431.
It is a strong prime.
It is an emirp because it is prime and its reverse (932424102431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134201424239 - 216 = 134201358703 is a prime.
Together with 134201424241, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 134201424199 and 134201424208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134201424209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67100712119 + 67100712120.
It is an arithmetic number, because the mean of its divisors is an integer number (67100712120).
Almost surely, 2134201424239 is an apocalyptic number.
134201424239 is a deficient number, since it is larger than the sum of its proper divisors (1).
134201424239 is an equidigital number, since it uses as much as digits as its factorization.
134201424239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 35.
The spelling of 134201424239 in words is "one hundred thirty-four billion, two hundred one million, four hundred twenty-four thousand, two hundred thirty-nine".
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