13420301113 has 2 divisors, whose sum is σ = 13420301114. Its totient is φ = 13420301112.

The previous prime is 13420301099. The next prime is 13420301123. The reversal of 13420301113 is 31110302431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10287436329 + 3132864784 = 101427^2 + 55972^2 .

It is a cyclic number.

It is not a de Polignac number, because 13420301113 - 2⁹ = 13420300601 is a prime.

It is not a weakly prime, because it can be changed into another prime (13420301123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710150556 + 6710150557.

It is an arithmetic number, because the mean of its divisors is an integer number (6710150557).

Almost surely, 2^13420301113 is an apocalyptic number.

It is an amenable number.

13420301113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13420301113 is an equidigital number, since it uses as much as digits as its factorization.

13420301113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13420301113 its reverse (31110302431), we get a palindrome (44530603544).

The spelling of 13420301113 in words is "thirteen billion, four hundred twenty million, three hundred one thousand, one hundred thirteen".