Base | Representation |
---|---|
bin | 10011100001110111010… |
… | …011111111000000101011 |
3 | 11202022000111002002120221 |
4 | 103201313103333000223 |
5 | 133441440032231013 |
6 | 2504304253030511 |
7 | 165646535510341 |
oct | 23416723770053 |
9 | 4668014062527 |
10 | 1342031523883 |
11 | 478174899196 |
12 | 198117785437 |
13 | 9972601082b |
14 | 48d51899991 |
15 | 24d98e4a08d |
hex | 138774ff02b |
1342031523883 has 2 divisors, whose sum is σ = 1342031523884. Its totient is φ = 1342031523882.
The previous prime is 1342031523869. The next prime is 1342031523901. The reversal of 1342031523883 is 3883251302431.
It is a weak prime.
It is an emirp because it is prime and its reverse (3883251302431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1342031523883 - 25 = 1342031523851 is a prime.
It is a super-2 number, since 2×13420315238832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1342031523853) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671015761941 + 671015761942.
It is an arithmetic number, because the mean of its divisors is an integer number (671015761942).
Almost surely, 21342031523883 is an apocalyptic number.
1342031523883 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342031523883 is an equidigital number, since it uses as much as digits as its factorization.
1342031523883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 414720, while the sum is 43.
The spelling of 1342031523883 in words is "one trillion, three hundred forty-two billion, thirty-one million, five hundred twenty-three thousand, eight hundred eighty-three".
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