Base | Representation |
---|---|
bin | 10011100001110111010… |
… | …011111111000010011111 |
3 | 11202022000111002002202020 |
4 | 103201313103333002133 |
5 | 133441440032231444 |
6 | 2504304253031223 |
7 | 165646535510565 |
oct | 23416723770237 |
9 | 4668014062666 |
10 | 1342031523999 |
11 | 478174899291 |
12 | 198117785513 |
13 | 997260108ba |
14 | 48d51899a35 |
15 | 24d98e4a119 |
hex | 138774ff09f |
1342031523999 has 4 divisors (see below), whose sum is σ = 1789375365336. Its totient is φ = 894687682664.
The previous prime is 1342031523983. The next prime is 1342031524019. The reversal of 1342031523999 is 9993251302431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1342031523999 - 24 = 1342031523983 is a prime.
It is a super-2 number, since 2×13420315239992 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1342031523949) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223671920664 + ... + 223671920669.
It is an arithmetic number, because the mean of its divisors is an integer number (447343841334).
Almost surely, 21342031523999 is an apocalyptic number.
1342031523999 is a deficient number, since it is larger than the sum of its proper divisors (447343841337).
1342031523999 is an equidigital number, since it uses as much as digits as its factorization.
1342031523999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 447343841336.
The product of its (nonzero) digits is 1574640, while the sum is 51.
The spelling of 1342031523999 in words is "one trillion, three hundred forty-two billion, thirty-one million, five hundred twenty-three thousand, nine hundred ninety-nine".
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