Search a number
-
+
1342031523949 is a prime number
BaseRepresentation
bin10011100001110111010…
…011111111000001101101
311202022000111002002200101
4103201313103333001231
5133441440032231244
62504304253031101
7165646535510464
oct23416723770155
94668014062611
101342031523949
11478174899246
12198117785491
139972601087c
1448d518999db
1524d98e4a0d4
hex138774ff06d

1342031523949 has 2 divisors, whose sum is σ = 1342031523950. Its totient is φ = 1342031523948.

The previous prime is 1342031523901. The next prime is 1342031523983. The reversal of 1342031523949 is 9493251302431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 991532003049 + 350499520900 = 995757^2 + 592030^2 .

It is a cyclic number.

It is not a de Polignac number, because 1342031523949 - 213 = 1342031515757 is a prime.

It is a super-2 number, since 2×13420315239492 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1342031523899 and 1342031523908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1342031523149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671015761974 + 671015761975.

It is an arithmetic number, because the mean of its divisors is an integer number (671015761975).

Almost surely, 21342031523949 is an apocalyptic number.

It is an amenable number.

1342031523949 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342031523949 is an equidigital number, since it uses as much as digits as its factorization.

1342031523949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 699840, while the sum is 46.

The spelling of 1342031523949 in words is "one trillion, three hundred forty-two billion, thirty-one million, five hundred twenty-three thousand, nine hundred forty-nine".