Base | Representation |
---|---|
bin | 111110011111100100… |
… | …1011111110100010001 |
3 | 110211101212110010211122 |
4 | 1330333021133310101 |
5 | 4144322040043101 |
6 | 141352513252025 |
7 | 12460454264432 |
oct | 1747711376421 |
9 | 424355403748 |
10 | 134203440401 |
11 | 51a08386118 |
12 | 22014564015 |
13 | c8699b6484 |
14 | 66d1859489 |
15 | 3756dc251b |
hex | 1f3f25fd11 |
134203440401 has 2 divisors, whose sum is σ = 134203440402. Its totient is φ = 134203440400.
The previous prime is 134203440377. The next prime is 134203440421. The reversal of 134203440401 is 104044302431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 85252320400 + 48951120001 = 291980^2 + 221249^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134203440401 is a prime.
It is not a weakly prime, because it can be changed into another prime (134203440421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67101720200 + 67101720201.
It is an arithmetic number, because the mean of its divisors is an integer number (67101720201).
Almost surely, 2134203440401 is an apocalyptic number.
It is an amenable number.
134203440401 is a deficient number, since it is larger than the sum of its proper divisors (1).
134203440401 is an equidigital number, since it uses as much as digits as its factorization.
134203440401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 134203440401 its reverse (104044302431), we get a palindrome (238247742832).
The spelling of 134203440401 in words is "one hundred thirty-four billion, two hundred three million, four hundred forty thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •