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134203440401 is a prime number
BaseRepresentation
bin111110011111100100…
…1011111110100010001
3110211101212110010211122
41330333021133310101
54144322040043101
6141352513252025
712460454264432
oct1747711376421
9424355403748
10134203440401
1151a08386118
1222014564015
13c8699b6484
1466d1859489
153756dc251b
hex1f3f25fd11

134203440401 has 2 divisors, whose sum is σ = 134203440402. Its totient is φ = 134203440400.

The previous prime is 134203440377. The next prime is 134203440421. The reversal of 134203440401 is 104044302431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85252320400 + 48951120001 = 291980^2 + 221249^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134203440401 is a prime.

It is not a weakly prime, because it can be changed into another prime (134203440421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67101720200 + 67101720201.

It is an arithmetic number, because the mean of its divisors is an integer number (67101720201).

Almost surely, 2134203440401 is an apocalyptic number.

It is an amenable number.

134203440401 is a deficient number, since it is larger than the sum of its proper divisors (1).

134203440401 is an equidigital number, since it uses as much as digits as its factorization.

134203440401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 134203440401 its reverse (104044302431), we get a palindrome (238247742832).

The spelling of 134203440401 in words is "one hundred thirty-four billion, two hundred three million, four hundred forty thousand, four hundred one".