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134211054003 = 3133441309077
BaseRepresentation
bin111110011111110011…
…0100010100110110011
3110211102101202221201220
41330333212202212303
54144331012212003
6141353344400123
712460606064505
oct1747746424663
9424371687656
10134211054003
1151a11706354
1222017016043
13c86b450a70
1466d287bd75
1537578c8353
hex1f3f9a29b3

134211054003 has 8 divisors (see below), whose sum is σ = 192713308368. Its totient is φ = 82591417824.

The previous prime is 134211054001. The next prime is 134211054013. The reversal of 134211054003 is 300450112431.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 134211054003 - 21 = 134211054001 is a prime.

It is not an unprimeable number, because it can be changed into a prime (134211054001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1720654500 + ... + 1720654577.

It is an arithmetic number, because the mean of its divisors is an integer number (24089163546).

Almost surely, 2134211054003 is an apocalyptic number.

134211054003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

134211054003 is a deficient number, since it is larger than the sum of its proper divisors (58502254365).

134211054003 is a wasteful number, since it uses less digits than its factorization.

134211054003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3441309093.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 134211054003 its reverse (300450112431), we get a palindrome (434661166434).

The spelling of 134211054003 in words is "one hundred thirty-four billion, two hundred eleven million, fifty-four thousand, three".

Divisors: 1 3 13 39 3441309077 10323927231 44737018001 134211054003