Base | Representation |
---|---|
bin | 111110011111110100… |
… | …0010111110100100001 |
3 | 110211102102200100022202 |
4 | 1330333220113310201 |
5 | 4144331123042423 |
6 | 141353402542545 |
7 | 12460613134316 |
oct | 1747750276441 |
9 | 424372610282 |
10 | 134211534113 |
11 | 51a11a04038 |
12 | 22017207a55 |
13 | c86b58b457 |
14 | 66d2964d0d |
15 | 3757970728 |
hex | 1f3fa17d21 |
134211534113 has 2 divisors, whose sum is σ = 134211534114. Its totient is φ = 134211534112.
The previous prime is 134211534103. The next prime is 134211534161. The reversal of 134211534113 is 311435112431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 119158207249 + 15053326864 = 345193^2 + 122692^2 .
It is a cyclic number.
It is not a de Polignac number, because 134211534113 - 24 = 134211534097 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (134211534103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67105767056 + 67105767057.
It is an arithmetic number, because the mean of its divisors is an integer number (67105767057).
Almost surely, 2134211534113 is an apocalyptic number.
It is an amenable number.
134211534113 is a deficient number, since it is larger than the sum of its proper divisors (1).
134211534113 is an equidigital number, since it uses as much as digits as its factorization.
134211534113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4320, while the sum is 29.
Adding to 134211534113 its reverse (311435112431), we get a palindrome (445646646544).
The spelling of 134211534113 in words is "one hundred thirty-four billion, two hundred eleven million, five hundred thirty-four thousand, one hundred thirteen".
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