Base | Representation |
---|---|
bin | 10011100001111101010… |
… | …000100111001001011001 |
3 | 11202022021102211101210211 |
4 | 103201331100213021121 |
5 | 133442141103144001 |
6 | 2504322215411121 |
7 | 165652156562506 |
oct | 23417520471131 |
9 | 4668242741724 |
10 | 1342131303001 |
11 | 478216149775 |
12 | 198145083aa1 |
13 | 997408a7928 |
14 | 48d60c304ad |
15 | 24da2aa9351 |
hex | 1387d427259 |
1342131303001 has 2 divisors, whose sum is σ = 1342131303002. Its totient is φ = 1342131303000.
The previous prime is 1342131302987. The next prime is 1342131303017. The reversal of 1342131303001 is 1003031312431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 676399329225 + 665731973776 = 822435^2 + 815924^2 .
It is an emirp because it is prime and its reverse (1003031312431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1342131303001 - 225 = 1342097748569 is a prime.
It is not a weakly prime, because it can be changed into another prime (1342131303041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671065651500 + 671065651501.
It is an arithmetic number, because the mean of its divisors is an integer number (671065651501).
Almost surely, 21342131303001 is an apocalyptic number.
It is an amenable number.
1342131303001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342131303001 is an equidigital number, since it uses as much as digits as its factorization.
1342131303001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1342131303001 its reverse (1003031312431), we get a palindrome (2345162615432).
The spelling of 1342131303001 in words is "one trillion, three hundred forty-two billion, one hundred thirty-one million, three hundred three thousand, one".
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