Base | Representation |
---|---|
bin | 11000111111111101… |
… | …01001111000011001 |
3 | 1021122100202210002202 |
4 | 30133332221320121 |
5 | 204441340420212 |
6 | 10055443335545 |
7 | 653411121353 |
oct | 143776517031 |
9 | 37570683082 |
10 | 13421420057 |
11 | 57680505a1 |
12 | 27269815b5 |
13 | 135b7a2b96 |
14 | 9147080d3 |
15 | 5384470c2 |
hex | 31ffa9e19 |
13421420057 has 2 divisors, whose sum is σ = 13421420058. Its totient is φ = 13421420056.
The previous prime is 13421420039. The next prime is 13421420093. The reversal of 13421420057 is 75002412431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12884293081 + 537126976 = 113509^2 + 23176^2 .
It is an emirp because it is prime and its reverse (75002412431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13421420057 - 224 = 13404642841 is a prime.
It is not a weakly prime, because it can be changed into another prime (13421420027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710710028 + 6710710029.
It is an arithmetic number, because the mean of its divisors is an integer number (6710710029).
Almost surely, 213421420057 is an apocalyptic number.
It is an amenable number.
13421420057 is a deficient number, since it is larger than the sum of its proper divisors (1).
13421420057 is an equidigital number, since it uses as much as digits as its factorization.
13421420057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 29.
Adding to 13421420057 its reverse (75002412431), we get a palindrome (88423832488).
The spelling of 13421420057 in words is "thirteen billion, four hundred twenty-one million, four hundred twenty thousand, fifty-seven".
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