Base | Representation |
---|---|
bin | 1100001101001110101111… |
… | …0000101100100110000010 |
3 | 1202112002001202111111201102 |
4 | 3003103223300230212002 |
5 | 3224344043402302114 |
6 | 44313415445334402 |
7 | 2553444425151344 |
oct | 303235360544602 |
9 | 52462052444642 |
10 | 13421433244034 |
11 | 4304aa8196612 |
12 | 16091b6a07402 |
13 | 7648358bc57a |
14 | 34585a997294 |
15 | 1841c7a5b2de |
hex | c34ebc2c982 |
13421433244034 has 4 divisors (see below), whose sum is σ = 20132149866054. Its totient is φ = 6710716622016.
The previous prime is 13421433244007. The next prime is 13421433244061. The reversal of 13421433244034 is 43044233412431.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (13421433244007) and next prime (13421433244061).
It can be written as a sum of positive squares in only one way, i.e., 7820708681809 + 5600724562225 = 2796553^2 + 2366585^2 .
It is a super-2 number, since 2×134214332440342 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3355358311007 + ... + 3355358311010.
Almost surely, 213421433244034 is an apocalyptic number.
13421433244034 is a deficient number, since it is larger than the sum of its proper divisors (6710716622020).
13421433244034 is an equidigital number, since it uses as much as digits as its factorization.
13421433244034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6710716622019.
The product of its (nonzero) digits is 331776, while the sum is 38.
Adding to 13421433244034 its reverse (43044233412431), we get a palindrome (56465666656465).
The spelling of 13421433244034 in words is "thirteen trillion, four hundred twenty-one billion, four hundred thirty-three million, two hundred forty-four thousand, thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •