Search a number
-
+
13421433244034 = 26710716622017
BaseRepresentation
bin1100001101001110101111…
…0000101100100110000010
31202112002001202111111201102
43003103223300230212002
53224344043402302114
644313415445334402
72553444425151344
oct303235360544602
952462052444642
1013421433244034
114304aa8196612
1216091b6a07402
137648358bc57a
1434585a997294
151841c7a5b2de
hexc34ebc2c982

13421433244034 has 4 divisors (see below), whose sum is σ = 20132149866054. Its totient is φ = 6710716622016.

The previous prime is 13421433244007. The next prime is 13421433244061. The reversal of 13421433244034 is 43044233412431.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13421433244007) and next prime (13421433244061).

It can be written as a sum of positive squares in only one way, i.e., 7820708681809 + 5600724562225 = 2796553^2 + 2366585^2 .

It is a super-2 number, since 2×134214332440342 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3355358311007 + ... + 3355358311010.

Almost surely, 213421433244034 is an apocalyptic number.

13421433244034 is a deficient number, since it is larger than the sum of its proper divisors (6710716622020).

13421433244034 is an equidigital number, since it uses as much as digits as its factorization.

13421433244034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6710716622019.

The product of its (nonzero) digits is 331776, while the sum is 38.

Adding to 13421433244034 its reverse (43044233412431), we get a palindrome (56465666656465).

The spelling of 13421433244034 in words is "thirteen trillion, four hundred twenty-one billion, four hundred thirty-three million, two hundred forty-four thousand, thirty-four".

Divisors: 1 2 6710716622017 13421433244034