Base | Representation |
---|---|
bin | 11001000000000100… |
… | …01101111001111001 |
3 | 1021122102112020021202 |
4 | 30200002031321321 |
5 | 204442110312131 |
6 | 10055515343545 |
7 | 653422061345 |
oct | 144002157171 |
9 | 37572466252 |
10 | 13422354041 |
11 | 5768629288 |
12 | 2727151bb5 |
13 | 135ba3c035 |
14 | 9148ac625 |
15 | 53857dbcb |
hex | 32008de79 |
13422354041 has 2 divisors, whose sum is σ = 13422354042. Its totient is φ = 13422354040.
The previous prime is 13422354031. The next prime is 13422354059. The reversal of 13422354041 is 14045322431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13126514041 + 295840000 = 114571^2 + 17200^2 .
It is a cyclic number.
It is not a de Polignac number, because 13422354041 - 210 = 13422353017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13422353995 and 13422354013.
It is not a weakly prime, because it can be changed into another prime (13422354031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711177020 + 6711177021.
It is an arithmetic number, because the mean of its divisors is an integer number (6711177021).
Almost surely, 213422354041 is an apocalyptic number.
It is an amenable number.
13422354041 is a deficient number, since it is larger than the sum of its proper divisors (1).
13422354041 is an equidigital number, since it uses as much as digits as its factorization.
13422354041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 13422354041 its reverse (14045322431), we get a palindrome (27467676472).
The spelling of 13422354041 in words is "thirteen billion, four hundred twenty-two million, three hundred fifty-four thousand, forty-one".
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