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1342255635481 is a prime number
BaseRepresentation
bin10011100010000100101…
…010111001110000011001
311202022121002210010220111
4103202010222321300121
5133442414420313411
62504342420324321
7165655226440045
oct23420452716031
94668532703814
101342255635481
1147827a34a592
1219817a8436a1
139976058a847
1448d73557025
1524dad968721
hex13884ab9c19

1342255635481 has 2 divisors, whose sum is σ = 1342255635482. Its totient is φ = 1342255635480.

The previous prime is 1342255635449. The next prime is 1342255635499. The reversal of 1342255635481 is 1845365522431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1080541539081 + 261714096400 = 1039491^2 + 511580^2 .

It is an emirp because it is prime and its reverse (1845365522431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1342255635481 - 25 = 1342255635449 is a prime.

It is a super-2 number, since 2×13422556354812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1342255635181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671127817740 + 671127817741.

It is an arithmetic number, because the mean of its divisors is an integer number (671127817741).

Almost surely, 21342255635481 is an apocalyptic number.

It is an amenable number.

1342255635481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342255635481 is an equidigital number, since it uses as much as digits as its factorization.

1342255635481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3456000, while the sum is 49.

The spelling of 1342255635481 in words is "one trillion, three hundred forty-two billion, two hundred fifty-five million, six hundred thirty-five thousand, four hundred eighty-one".