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1342261041553 is a prime number
BaseRepresentation
bin10011100010000100111…
…111100001100110010001
311202022121110221210122101
4103202010333201212101
5133442422311312203
62504343132240401
7165655323414145
oct23420477414621
94668543853571
101342261041553
11478282402213
12198180610101
13997617313c3
1448d74163225
1524dae18541d
hex13884fe1991

1342261041553 has 2 divisors, whose sum is σ = 1342261041554. Its totient is φ = 1342261041552.

The previous prime is 1342261041547. The next prime is 1342261041557. The reversal of 1342261041553 is 3551401622431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 716616427024 + 625644614529 = 846532^2 + 790977^2 .

It is a cyclic number.

It is not a de Polignac number, because 1342261041553 - 29 = 1342261041041 is a prime.

It is not a weakly prime, because it can be changed into another prime (1342261041557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671130520776 + 671130520777.

It is an arithmetic number, because the mean of its divisors is an integer number (671130520777).

Almost surely, 21342261041553 is an apocalyptic number.

It is an amenable number.

1342261041553 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342261041553 is an equidigital number, since it uses as much as digits as its factorization.

1342261041553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 1342261041553 its reverse (3551401622431), we get a palindrome (4893662663984).

The spelling of 1342261041553 in words is "one trillion, three hundred forty-two billion, two hundred sixty-one million, forty-one thousand, five hundred fifty-three".