Base | Representation |
---|---|
bin | 111110100000010001… |
… | …1100001110100000011 |
3 | 110211110111212012111212 |
4 | 1331000203201310003 |
5 | 4144344110312124 |
6 | 141355115200335 |
7 | 12461162012423 |
oct | 1750043416403 |
9 | 424414765455 |
10 | 134227041539 |
11 | 51a1a735a98 |
12 | 220204460ab |
13 | c87185aa46 |
14 | 66d4a40483 |
15 | 3758ed540e |
hex | 1f408e1d03 |
134227041539 has 2 divisors, whose sum is σ = 134227041540. Its totient is φ = 134227041538.
The previous prime is 134227041479. The next prime is 134227041551. The reversal of 134227041539 is 935140722431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134227041539 - 28 = 134227041283 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134227041496 and 134227041505.
It is not a weakly prime, because it can be changed into another prime (134227041139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67113520769 + 67113520770.
It is an arithmetic number, because the mean of its divisors is an integer number (67113520770).
Almost surely, 2134227041539 is an apocalyptic number.
134227041539 is a deficient number, since it is larger than the sum of its proper divisors (1).
134227041539 is an equidigital number, since it uses as much as digits as its factorization.
134227041539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 41.
The spelling of 134227041539 in words is "one hundred thirty-four billion, two hundred twenty-seven million, forty-one thousand, five hundred thirty-nine".
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