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13423097926081 is a prime number
BaseRepresentation
bin1100001101010100111011…
…1110111101000111000001
31202112020100202220010012001
43003111032332331013001
53224411001032113311
644314252553304001
72553533610545644
oct303251676750701
952466322803161
1013423097926081
1143057819268a8
1216095a0405001
13764a3c75142c
14345977ac7a5b
15184273c854c1
hexc354efbd1c1

13423097926081 has 2 divisors, whose sum is σ = 13423097926082. Its totient is φ = 13423097926080.

The previous prime is 13423097926057. The next prime is 13423097926103. The reversal of 13423097926081 is 18062979032431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13421664546481 + 1433379600 = 3663559^2 + 37860^2 .

It is a cyclic number.

It is not a de Polignac number, because 13423097926081 - 221 = 13423095828929 is a prime.

It is a super-2 number, since 2×134230979260812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13423097924081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711548963040 + 6711548963041.

It is an arithmetic number, because the mean of its divisors is an integer number (6711548963041).

Almost surely, 213423097926081 is an apocalyptic number.

It is an amenable number.

13423097926081 is a deficient number, since it is larger than the sum of its proper divisors (1).

13423097926081 is an equidigital number, since it uses as much as digits as its factorization.

13423097926081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3919104, while the sum is 55.

The spelling of 13423097926081 in words is "thirteen trillion, four hundred twenty-three billion, ninety-seven million, nine hundred twenty-six thousand, eighty-one".