Base | Representation |
---|---|
bin | 111110100000011001… |
… | …1110100010001011111 |
3 | 110211110210220010201220 |
4 | 1331000303310101133 |
5 | 4144401203431310 |
6 | 141355350504423 |
7 | 12461243215233 |
oct | 1750063642137 |
9 | 424423803656 |
10 | 134231311455 |
11 | 51a2209204a |
12 | 22021965113 |
13 | c8726c4417 |
14 | 66d54325c3 |
15 | 375957a670 |
hex | 1f40cf445f |
134231311455 has 32 divisors (see below), whose sum is σ = 221761566720. Its totient is φ = 69260864640.
The previous prime is 134231311447. The next prime is 134231311463. The reversal of 134231311455 is 554113132431.
It is an interprime number because it is at equal distance from previous prime (134231311447) and next prime (134231311463).
It is not a de Polignac number, because 134231311455 - 23 = 134231311447 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1661989 + ... + 1740881.
It is an arithmetic number, because the mean of its divisors is an integer number (6930048960).
Almost surely, 2134231311455 is an apocalyptic number.
134231311455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
134231311455 is a deficient number, since it is larger than the sum of its proper divisors (87530255265).
134231311455 is a wasteful number, since it uses less digits than its factorization.
134231311455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82591.
The product of its digits is 21600, while the sum is 33.
Adding to 134231311455 its reverse (554113132431), we get a palindrome (688344443886).
The spelling of 134231311455 in words is "one hundred thirty-four billion, two hundred thirty-one million, three hundred eleven thousand, four hundred fifty-five".
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