Base | Representation |
---|---|
bin | 10011100010001001001… |
… | …011001101000111101011 |
3 | 11202022210100222211202201 |
4 | 103202021023031013223 |
5 | 133443043242243032 |
6 | 2504354120241031 |
7 | 165660135021403 |
oct | 23421113150753 |
9 | 4668710884681 |
10 | 1342331212267 |
11 | 478308a7a541 |
12 | 1981a0010177 |
13 | 9977312c836 |
14 | 48d7d5cb803 |
15 | 24db53e68e7 |
hex | 138892cd1eb |
1342331212267 has 2 divisors, whose sum is σ = 1342331212268. Its totient is φ = 1342331212266.
The previous prime is 1342331212253. The next prime is 1342331212337. The reversal of 1342331212267 is 7622121332431.
It is a weak prime.
It is an emirp because it is prime and its reverse (7622121332431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1342331212267 - 215 = 1342331179499 is a prime.
It is a super-2 number, since 2×13423312122672 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1342331212247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671165606133 + 671165606134.
It is an arithmetic number, because the mean of its divisors is an integer number (671165606134).
Almost surely, 21342331212267 is an apocalyptic number.
1342331212267 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342331212267 is an equidigital number, since it uses as much as digits as its factorization.
1342331212267 is an evil number, because the sum of its binary digits is even.
The product of its digits is 72576, while the sum is 37.
Adding to 1342331212267 its reverse (7622121332431), we get a palindrome (8964452544698).
The spelling of 1342331212267 in words is "one trillion, three hundred forty-two billion, three hundred thirty-one million, two hundred twelve thousand, two hundred sixty-seven".
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