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13423355542013 = 18717174428403
BaseRepresentation
bin1100001101010101111001…
…0101101011100111111101
31202112021000201122100210212
43003111132111223213331
53224412013004321023
644314334315042205
72553543156340544
oct303253625534775
952467021570725
1013423355542013
1143058a429152a
121609652740365
13764a80c2c4b1
1434599ddc715b
1518428b6c0e78
hexc355e56b9fd

13423355542013 has 4 divisors (see below), whose sum is σ = 13430529972288. Its totient is φ = 13416181111740.

The previous prime is 13423355541923. The next prime is 13423355542021. The reversal of 13423355542013 is 31024555332431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13423355542013 - 228 = 13423087106557 is a prime.

It is a super-2 number, since 2×134233555420132 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13423355542043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3587212331 + ... + 3587216072.

It is an arithmetic number, because the mean of its divisors is an integer number (3357632493072).

Almost surely, 213423355542013 is an apocalyptic number.

It is an amenable number.

13423355542013 is a deficient number, since it is larger than the sum of its proper divisors (7174430275).

13423355542013 is an equidigital number, since it uses as much as digits as its factorization.

13423355542013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7174430274.

The product of its (nonzero) digits is 648000, while the sum is 41.

The spelling of 13423355542013 in words is "thirteen trillion, four hundred twenty-three billion, three hundred fifty-five million, five hundred forty-two thousand, thirteen".

Divisors: 1 1871 7174428403 13423355542013