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13423355542021 is a prime number
BaseRepresentation
bin1100001101010101111001…
…0101101011101000000101
31202112021000201122100211011
43003111132111223220011
53224412013004321041
644314334315042221
72553543156340555
oct303253625535005
952467021570734
1013423355542021
1143058a4291537
121609652740371
13764a80c2c4b9
1434599ddc7165
1518428b6c0e81
hexc355e56ba05

13423355542021 has 2 divisors, whose sum is σ = 13423355542022. Its totient is φ = 13423355542020.

The previous prime is 13423355541923. The next prime is 13423355542043. The reversal of 13423355542021 is 12024555332431.

13423355542021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13423027425025 + 328116996 = 3663745^2 + 18114^2 .

It is an emirp because it is prime and its reverse (12024555332431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13423355542021 - 213 = 13423355533829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13423355542081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711677771010 + 6711677771011.

It is an arithmetic number, because the mean of its divisors is an integer number (6711677771011).

Almost surely, 213423355542021 is an apocalyptic number.

It is an amenable number.

13423355542021 is a deficient number, since it is larger than the sum of its proper divisors (1).

13423355542021 is an equidigital number, since it uses as much as digits as its factorization.

13423355542021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432000, while the sum is 40.

The spelling of 13423355542021 in words is "thirteen trillion, four hundred twenty-three billion, three hundred fifty-five million, five hundred forty-two thousand, twenty-one".