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13423401200000 = 2755113191327
BaseRepresentation
bin1100001101010110000100…
…0011110110100110000000
31202112021010220120000210102
43003111201003312212000
53224412111201400000
644314343025421532
72553544252412321
oct303254103664600
952467126500712
1013423401200000
114305918037000
121609665a9a8a8
13764a8a52745c
143459a60b0448
151842906de3d5
hexc35610f6980

13423401200000 has 768 divisors, whose sum is σ = 38729471155200. Its totient is φ = 4620844800000.

The previous prime is 13423401199973. The next prime is 13423401200003. The reversal of 13423401200000 is 210432431.

It is a super-2 number, since 2×134234012000002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13423401200003) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 10115599337 + ... + 10115600663.

It is an arithmetic number, because the mean of its divisors is an integer number (50428998900).

Almost surely, 213423401200000 is an apocalyptic number.

13423401200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13423401200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19364735577600).

13423401200000 is an abundant number, since it is smaller than the sum of its proper divisors (25306069955200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13423401200000 is an frugal number, since it uses more digits than its factorization.

13423401200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1418 (or 1364 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 13423401200000 its reverse (210432431), we get a palindrome (13423611632431).

The spelling of 13423401200000 in words is "thirteen trillion, four hundred twenty-three billion, four hundred one million, two hundred thousand".