Base | Representation |
---|---|
bin | 1100001101010110000100… |
… | …1111000000101101001101 |
3 | 1202112021011010001122010221 |
4 | 3003111201033000231031 |
5 | 3224412112424000010 |
6 | 44314343212231341 |
7 | 2553544316314120 |
oct | 303254117005515 |
9 | 52467133048127 |
10 | 13423404125005 |
11 | 4305919754666 |
12 | 1609666a6b551 |
13 | 764a8b00c924 |
14 | 3459a66323b7 |
15 | 184290abadda |
hex | c35613c0b4d |
13423404125005 has 8 divisors (see below), whose sum is σ = 18409239942912. Its totient is φ = 9204619971408.
The previous prime is 13423404124937. The next prime is 13423404125009. The reversal of 13423404125005 is 50052140432431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13423404125005 - 211 = 13423404122957 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13423404125009) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 191762916037 + ... + 191762916106.
It is an arithmetic number, because the mean of its divisors is an integer number (2301154992864).
Almost surely, 213423404125005 is an apocalyptic number.
It is an amenable number.
13423404125005 is a deficient number, since it is larger than the sum of its proper divisors (4985835817907).
13423404125005 is an equidigital number, since it uses as much as digits as its factorization.
13423404125005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 383525832155.
The product of its (nonzero) digits is 57600, while the sum is 34.
Adding to 13423404125005 its reverse (50052140432431), we get a palindrome (63475544557436).
The spelling of 13423404125005 in words is "thirteen trillion, four hundred twenty-three billion, four hundred four million, one hundred twenty-five thousand, five".
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