Base | Representation |
---|---|
bin | 1100001101010110001011… |
… | …0110011011001111110011 |
3 | 1202112021020000001221110001 |
4 | 3003111202312123033303 |
5 | 3224412141344001142 |
6 | 44314350021250431 |
7 | 2553545065613515 |
oct | 303254266331763 |
9 | 52467200057401 |
10 | 13423431234547 |
11 | 4305932a90444 |
12 | 1609673b63a17 |
13 | 764a93812089 |
14 | 3459aa08bbb5 |
15 | 1842931735b7 |
hex | c3562d9b3f3 |
13423431234547 has 2 divisors, whose sum is σ = 13423431234548. Its totient is φ = 13423431234546.
The previous prime is 13423431234403. The next prime is 13423431234559. The reversal of 13423431234547 is 74543213432431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13423431234547 - 227 = 13423297016819 is a prime.
It is a super-2 number, since 2×134234312345472 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13423431234497 and 13423431234506.
It is not a weakly prime, because it can be changed into another prime (13423431234047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711715617273 + 6711715617274.
It is an arithmetic number, because the mean of its divisors is an integer number (6711715617274).
Almost surely, 213423431234547 is an apocalyptic number.
13423431234547 is a deficient number, since it is larger than the sum of its proper divisors (1).
13423431234547 is an equidigital number, since it uses as much as digits as its factorization.
13423431234547 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2903040, while the sum is 46.
Adding to 13423431234547 its reverse (74543213432431), we get a palindrome (87966644666978).
The spelling of 13423431234547 in words is "thirteen trillion, four hundred twenty-three billion, four hundred thirty-one million, two hundred thirty-four thousand, five hundred forty-seven".
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