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13423540440073 is a prime number
BaseRepresentation
bin1100001101010110100101…
…0111000000110000001001
31202112021111121120011021011
43003111221113000300021
53224412402323040243
644314404522043521
72553550563056131
oct303255127006011
952467447504234
1013423540440073
11430598969a145
1216096a46495a1
13764ab032992a
143459ba797ac1
1518429ca4589d
hexc35695c0c09

13423540440073 has 2 divisors, whose sum is σ = 13423540440074. Its totient is φ = 13423540440072.

The previous prime is 13423540439987. The next prime is 13423540440103. The reversal of 13423540440073 is 37004404532431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8024483893504 + 5399056546569 = 2832752^2 + 2323587^2 .

It is a cyclic number.

It is not a de Polignac number, because 13423540440073 - 213 = 13423540431881 is a prime.

It is not a weakly prime, because it can be changed into another prime (13423540440773) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711770220036 + 6711770220037.

It is an arithmetic number, because the mean of its divisors is an integer number (6711770220037).

Almost surely, 213423540440073 is an apocalyptic number.

It is an amenable number.

13423540440073 is a deficient number, since it is larger than the sum of its proper divisors (1).

13423540440073 is an equidigital number, since it uses as much as digits as its factorization.

13423540440073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 483840, while the sum is 40.

The spelling of 13423540440073 in words is "thirteen trillion, four hundred twenty-three billion, five hundred forty million, four hundred forty thousand, seventy-three".