134240001403 has 2 divisors, whose sum is σ = 134240001404. Its totient is φ = 134240001402.

The previous prime is 134240001367. The next prime is 134240001409. The reversal of 134240001403 is 304100042431.

It is a strong prime.

It is an emirp because it is prime and its reverse (304100042431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134240001403 is a prime.

It is a super-3 number, since 3×134240001403³ (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (134240001409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67120000701 + 67120000702.

It is an arithmetic number, because the mean of its divisors is an integer number (67120000702).

Almost surely, 2^134240001403 is an apocalyptic number.

134240001403 is a deficient number, since it is larger than the sum of its proper divisors (1).

134240001403 is an equidigital number, since it uses as much as digits as its factorization.

134240001403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 134240001403 its reverse (304100042431), we get a palindrome (438340043834).

The spelling of 134240001403 in words is "one hundred thirty-four billion, two hundred forty million, one thousand, four hundred three".