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13424240010044 = 2231108260000081
BaseRepresentation
bin1100001101011001001100…
…0011101010001100111100
31202112100022100220222212002
43003112103003222030330
53224420320420310134
644315002152201432
72553604116236543
oct303262303521474
952470270828762
1013424240010044
114306208575446
12160985a999278
13764b92248366
14345a4565d15a
151842de18087e
hexc35930ea33c

13424240010044 has 12 divisors (see below), whose sum is σ = 24250240018368. Its totient is φ = 6495600004800.

The previous prime is 13424240010029. The next prime is 13424240010163. The reversal of 13424240010044 is 44001004242431.

It is a super-2 number, since 2×134242400100442 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13424240009989 and 13424240010016.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54129999917 + ... + 54130000164.

It is an arithmetic number, because the mean of its divisors is an integer number (2020853334864).

Almost surely, 213424240010044 is an apocalyptic number.

It is an amenable number.

13424240010044 is a deficient number, since it is larger than the sum of its proper divisors (10826000008324).

13424240010044 is a wasteful number, since it uses less digits than its factorization.

13424240010044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108260000116 (or 108260000114 counting only the distinct ones).

The product of its (nonzero) digits is 12288, while the sum is 29.

Adding to 13424240010044 its reverse (44001004242431), we get a palindrome (57425244252475).

The spelling of 13424240010044 in words is "thirteen trillion, four hundred twenty-four billion, two hundred forty million, ten thousand, forty-four".

Divisors: 1 2 4 31 62 124 108260000081 216520000162 433040000324 3356060002511 6712120005022 13424240010044