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1342443551 = 9971346483
BaseRepresentation
bin101000000000100…
…0001000000011111
310110120001012100112
41100001001000133
510222131143201
6341113120235
745160403411
oct12001010037
93416035315
101342443551
11629857789
123156b907b
13185178ac7
14ca40c9b1
157ccc60bb
hex5004101f

1342443551 has 4 divisors (see below), whose sum is σ = 1343791032. Its totient is φ = 1341096072.

The previous prime is 1342443547. The next prime is 1342443569. The reversal of 1342443551 is 1553442431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1553442431 = 14891043279.

It is a cyclic number.

It is not a de Polignac number, because 1342443551 - 22 = 1342443547 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1342443511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 672245 + ... + 674238.

It is an arithmetic number, because the mean of its divisors is an integer number (335947758).

Almost surely, 21342443551 is an apocalyptic number.

1342443551 is a deficient number, since it is larger than the sum of its proper divisors (1347481).

1342443551 is an equidigital number, since it uses as much as digits as its factorization.

1342443551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1347480.

The product of its digits is 28800, while the sum is 32.

The square root of 1342443551 is about 36639.3715966854. The cubic root of 1342443551 is about 1103.1435015566.

Adding to 1342443551 its reverse (1553442431), we get a palindrome (2895885982).

The spelling of 1342443551 in words is "one billion, three hundred forty-two million, four hundred forty-three thousand, five hundred fifty-one".

Divisors: 1 997 1346483 1342443551