13424505330113 has 2 divisors, whose sum is σ = 13424505330114. Its totient is φ = 13424505330112.

The previous prime is 13424505330017. The next prime is 13424505330121. The reversal of 13424505330113 is 31103350542431.

13424505330113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8816665288369 + 4607840041744 = 2969287^2 + 2146588^2 .

It is an emirp because it is prime and its reverse (31103350542431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13424505330113 - 2²⁴ = 13424488552897 is a prime.

It is a super-3 number, since 3×13424505330113³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13424505330163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712252665056 + 6712252665057.

It is an arithmetic number, because the mean of its divisors is an integer number (6712252665057).

Almost surely, 2^{13424505330113} is an apocalyptic number.

It is an amenable number.

13424505330113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13424505330113 is an equidigital number, since it uses as much as digits as its factorization.

13424505330113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 13424505330113 its reverse (31103350542431), we get a palindrome (44527855872544).

The spelling of 13424505330113 in words is "thirteen trillion, four hundred twenty-four billion, five hundred five million, three hundred thirty thousand, one hundred thirteen".