Base | Representation |
---|---|
bin | 10011100010010011111… |
… | …110111110000010000001 |
3 | 11202100021000012222000101 |
4 | 103202103332332002001 |
5 | 133443431203212423 |
6 | 2504424115122401 |
7 | 165664466266003 |
oct | 23422376760201 |
9 | 4670230188011 |
10 | 1342512554113 |
11 | 4783a1379335 |
12 | 1982308a3401 |
13 | 997a18833c3 |
14 | 48d99714373 |
15 | 24dc62b77ad |
hex | 13893fbe081 |
1342512554113 has 2 divisors, whose sum is σ = 1342512554114. Its totient is φ = 1342512554112.
The previous prime is 1342512554077. The next prime is 1342512554171. The reversal of 1342512554113 is 3114552152431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 826921059904 + 515591494209 = 909352^2 + 718047^2 .
It is a cyclic number.
It is not a de Polignac number, because 1342512554113 - 225 = 1342478999681 is a prime.
It is not a weakly prime, because it can be changed into another prime (1342512558113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671256277056 + 671256277057.
It is an arithmetic number, because the mean of its divisors is an integer number (671256277057).
Almost surely, 21342512554113 is an apocalyptic number.
It is an amenable number.
1342512554113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342512554113 is an equidigital number, since it uses as much as digits as its factorization.
1342512554113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 72000, while the sum is 37.
The spelling of 1342512554113 in words is "one trillion, three hundred forty-two billion, five hundred twelve million, five hundred fifty-four thousand, one hundred thirteen".
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