Base | Representation |
---|---|
bin | 11001000000011001… |
… | …10110010111111001 |
3 | 1021122121202211121101 |
4 | 30200030312113321 |
5 | 204443314004431 |
6 | 10100055211401 |
7 | 653454550321 |
oct | 144014662771 |
9 | 37577684541 |
10 | 13425141241 |
11 | 576a162356 |
12 | 2728076b61 |
13 | 135c4a6875 |
14 | 914dd6281 |
15 | 53892e961 |
hex | 3203365f9 |
13425141241 has 16 divisors (see below), whose sum is σ = 14040601344. Its totient is φ = 12823905024.
The previous prime is 13425141227. The next prime is 13425141251. The reversal of 13425141241 is 14214152431.
It is a happy number.
13425141241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13425141241 - 211 = 13425139193 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13425141211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4632705 + ... + 4635601.
It is an arithmetic number, because the mean of its divisors is an integer number (877537584).
Almost surely, 213425141241 is an apocalyptic number.
It is an amenable number.
13425141241 is a deficient number, since it is larger than the sum of its proper divisors (615460103).
13425141241 is a wasteful number, since it uses less digits than its factorization.
13425141241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5280.
The product of its digits is 3840, while the sum is 28.
Adding to 13425141241 its reverse (14214152431), we get a palindrome (27639293672).
The spelling of 13425141241 in words is "thirteen billion, four hundred twenty-five million, one hundred forty-one thousand, two hundred forty-one".
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