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134252124442 = 267126062221
BaseRepresentation
bin111110100001000001…
…1001101100100011010
3110211112021001112210021
41331002003031210122
54144422020440232
6141401412541054
712461615141422
oct1750203154432
9424467045707
10134252124442
1151a32908167
122202892178a
13c876b008b7
1466d80cd482
15375b2dc397
hex1f420cd91a

134252124442 has 4 divisors (see below), whose sum is σ = 201378186666. Its totient is φ = 67126062220.

The previous prime is 134252124431. The next prime is 134252124451. The reversal of 134252124442 is 244421252431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 79281101761 + 54971022681 = 281569^2 + 234459^2 .

It is a super-2 number, since 2×1342521244422 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134252124398 and 134252124407.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33563031109 + ... + 33563031112.

Almost surely, 2134252124442 is an apocalyptic number.

134252124442 is a deficient number, since it is larger than the sum of its proper divisors (67126062224).

134252124442 is an equidigital number, since it uses as much as digits as its factorization.

134252124442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67126062223.

The product of its digits is 61440, while the sum is 34.

Adding to 134252124442 its reverse (244421252431), we get a palindrome (378673376873).

The spelling of 134252124442 in words is "one hundred thirty-four billion, two hundred fifty-two million, one hundred twenty-four thousand, four hundred forty-two".

Divisors: 1 2 67126062221 134252124442