Base | Representation |
---|---|
bin | 111110100001000011… |
… | …1010101001100100111 |
3 | 110211112100002102000122 |
4 | 1331002013111030213 |
5 | 4144422310014023 |
6 | 141401452032155 |
7 | 12461630256533 |
oct | 1750207251447 |
9 | 424470072018 |
10 | 134253204263 |
11 | 51a33485482 |
12 | 2202916265b |
13 | c8770bb249 |
14 | 66d82d0bc3 |
15 | 375b4522c8 |
hex | 1f421d5327 |
134253204263 has 4 divisors (see below), whose sum is σ = 137375371848. Its totient is φ = 131131036680.
The previous prime is 134253204247. The next prime is 134253204269. The reversal of 134253204263 is 362402352431.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134253204263 - 24 = 134253204247 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134253204269) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1561083728 + ... + 1561083813.
It is an arithmetic number, because the mean of its divisors is an integer number (34343842962).
Almost surely, 2134253204263 is an apocalyptic number.
134253204263 is a deficient number, since it is larger than the sum of its proper divisors (3122167585).
134253204263 is an equidigital number, since it uses as much as digits as its factorization.
134253204263 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3122167584.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 134253204263 its reverse (362402352431), we get a palindrome (496655556694).
The spelling of 134253204263 in words is "one hundred thirty-four billion, two hundred fifty-three million, two hundred four thousand, two hundred sixty-three".
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