Base | Representation |
---|---|
bin | 11110100001110000111111… |
… | …110011011111110011000110 |
3 | 122121101022001002000001022021 |
4 | 132201300333303133303012 |
5 | 120044221030010342113 |
6 | 1153314555014553354 |
7 | 40165043165160235 |
oct | 3641607763376306 |
9 | 577338032001267 |
10 | 134261748137158 |
11 | 398640a6699404 |
12 | 130849ab96885a |
13 | 59bbaa035ba45 |
14 | 25224362c8b1c |
15 | 107c6c993c48d |
hex | 7a1c3fcdfcc6 |
134261748137158 has 4 divisors (see below), whose sum is σ = 201392622205740. Its totient is φ = 67130874068578.
The previous prime is 134261748137147. The next prime is 134261748137213. The reversal of 134261748137158 is 851731847162431.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×1342617481371583 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134261748137096 and 134261748137105.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33565437034288 + ... + 33565437034291.
It is an arithmetic number, because the mean of its divisors is an integer number (50348155551435).
Almost surely, 2134261748137158 is an apocalyptic number.
134261748137158 is a deficient number, since it is larger than the sum of its proper divisors (67130874068582).
134261748137158 is an equidigital number, since it uses as much as digits as its factorization.
134261748137158 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67130874068581.
The product of its digits is 27095040, while the sum is 61.
The spelling of 134261748137158 in words is "one hundred thirty-four trillion, two hundred sixty-one billion, seven hundred forty-eight million, one hundred thirty-seven thousand, one hundred fifty-eight".
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