Base | Representation |
---|---|
bin | 111110100001010111… |
… | …0101100111110111011 |
3 | 110211120001111202211112 |
4 | 1331002232230332323 |
5 | 4144432430302212 |
6 | 141402501150535 |
7 | 12462114064202 |
oct | 1750256547673 |
9 | 424501452745 |
10 | 134263525307 |
11 | 51a3929486a |
12 | 220306bb44b |
13 | c879292c82 |
14 | 66d981a239 |
15 | 375c2e0422 |
hex | 1f42bacfbb |
134263525307 has 2 divisors, whose sum is σ = 134263525308. Its totient is φ = 134263525306.
The previous prime is 134263525303. The next prime is 134263525321. The reversal of 134263525307 is 703525362431.
It is a weak prime.
It is an emirp because it is prime and its reverse (703525362431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134263525307 - 22 = 134263525303 is a prime.
It is not a weakly prime, because it can be changed into another prime (134263525303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67131762653 + 67131762654.
It is an arithmetic number, because the mean of its divisors is an integer number (67131762654).
Almost surely, 2134263525307 is an apocalyptic number.
134263525307 is a deficient number, since it is larger than the sum of its proper divisors (1).
134263525307 is an equidigital number, since it uses as much as digits as its factorization.
134263525307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 453600, while the sum is 41.
Adding to 134263525307 its reverse (703525362431), we get a palindrome (837788887738).
The spelling of 134263525307 in words is "one hundred thirty-four billion, two hundred sixty-three million, five hundred twenty-five thousand, three hundred seven".
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