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134265420526513 is a prime number
BaseRepresentation
bin11110100001110100011010…
…101100100011001110110001
3122121101122112000020202102211
4132201310122230203032301
5120044301040123322023
61153320403243012121
740165233200026603
oct3641643254431661
9577348460222384
10134265420526513
113986571065a931
121308565580a041
1359bc2371360b3
1425226a3d1d173
15107c84204ca0d
hex7a1d1ab233b1

134265420526513 has 2 divisors, whose sum is σ = 134265420526514. Its totient is φ = 134265420526512.

The previous prime is 134265420526507. The next prime is 134265420526537. The reversal of 134265420526513 is 315625024562431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106778804224689 + 27486616301824 = 10333383^2 + 5242768^2 .

It is a cyclic number.

It is not a de Polignac number, because 134265420526513 - 217 = 134265420395441 is a prime.

It is a super-2 number, since 2×1342654205265132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134265420526543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67132710263256 + 67132710263257.

It is an arithmetic number, because the mean of its divisors is an integer number (67132710263257).

Almost surely, 2134265420526513 is an apocalyptic number.

It is an amenable number.

134265420526513 is a deficient number, since it is larger than the sum of its proper divisors (1).

134265420526513 is an equidigital number, since it uses as much as digits as its factorization.

134265420526513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184000, while the sum is 49.

The spelling of 134265420526513 in words is "one hundred thirty-four trillion, two hundred sixty-five billion, four hundred twenty million, five hundred twenty-six thousand, five hundred thirteen".