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134265441015406 = 267132720507703
BaseRepresentation
bin11110100001110100011011…
…111010101101011001101110
3122121101122120102210200220201
4132201310123322231121232
5120044301110344443111
61153320405254104114
740165233536133151
oct3641643372553156
9577348512720821
10134265441015406
11398657211844a8
121308566064b03a
1359bc23b45abbc
1425226a6933c98
15107c843c486c1
hex7a1d1bead66e

134265441015406 has 4 divisors (see below), whose sum is σ = 201398161523112. Its totient is φ = 67132720507702.

The previous prime is 134265441015331. The next prime is 134265441015427. The reversal of 134265441015406 is 604510144562431.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1342654410154062 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33566360253850 + ... + 33566360253853.

It is an arithmetic number, because the mean of its divisors is an integer number (50349540380778).

Almost surely, 2134265441015406 is an apocalyptic number.

134265441015406 is a deficient number, since it is larger than the sum of its proper divisors (67132720507706).

134265441015406 is an equidigital number, since it uses as much as digits as its factorization.

134265441015406 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67132720507705.

The product of its (nonzero) digits is 1382400, while the sum is 46.

Adding to 134265441015406 its reverse (604510144562431), we get a palindrome (738775585577837).

The spelling of 134265441015406 in words is "one hundred thirty-four trillion, two hundred sixty-five billion, four hundred forty-one million, fifteen thousand, four hundred six".

Divisors: 1 2 67132720507703 134265441015406