Base | Representation |
---|---|
bin | 1100001101101111110011… |
… | …1100010000000000101011 |
3 | 1202112220222111100120111112 |
4 | 3003123330330100000223 |
5 | 3230020234210414242 |
6 | 44321444435420535 |
7 | 2554210431333212 |
oct | 303337474200053 |
9 | 52486874316445 |
10 | 13430311419947 |
11 | 430884373a584 |
12 | 160aa7415474b |
13 | 76561c0575b6 |
14 | 34605db3a079 |
15 | 1845471c1c82 |
hex | c36fcf1002b |
13430311419947 has 2 divisors, whose sum is σ = 13430311419948. Its totient is φ = 13430311419946.
The previous prime is 13430311419937. The next prime is 13430311420033. The reversal of 13430311419947 is 74991411303431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13430311419947 - 226 = 13430244311083 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13430311419895 and 13430311419904.
It is not a weakly prime, because it can be changed into another prime (13430311419937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715155709973 + 6715155709974.
It is an arithmetic number, because the mean of its divisors is an integer number (6715155709974).
Almost surely, 213430311419947 is an apocalyptic number.
13430311419947 is a deficient number, since it is larger than the sum of its proper divisors (1).
13430311419947 is an equidigital number, since it uses as much as digits as its factorization.
13430311419947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 979776, while the sum is 50.
The spelling of 13430311419947 in words is "thirteen trillion, four hundred thirty billion, three hundred eleven million, four hundred nineteen thousand, nine hundred forty-seven".
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