Base | Representation |
---|---|
bin | 1100001101110000010000… |
… | …1101001100011101001011 |
3 | 1202112221021222200211201111 |
4 | 3003130010031030131023 |
5 | 3230021011411133342 |
6 | 44321504512031151 |
7 | 2554213441324405 |
oct | 303340415143513 |
9 | 52487258624644 |
10 | 13430433302347 |
11 | 43088a6517636 |
12 | 160aaa8b324b7 |
13 | 76563b390269 |
14 | 346071dc5b75 |
15 | 184552c4a217 |
hex | c370434c74b |
13430433302347 has 2 divisors, whose sum is σ = 13430433302348. Its totient is φ = 13430433302346.
The previous prime is 13430433302243. The next prime is 13430433302381. The reversal of 13430433302347 is 74320333403431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13430433302347 - 211 = 13430433300299 is a prime.
It is not a weakly prime, because it can be changed into another prime (13430433305347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715216651173 + 6715216651174.
It is an arithmetic number, because the mean of its divisors is an integer number (6715216651174).
Almost surely, 213430433302347 is an apocalyptic number.
13430433302347 is a deficient number, since it is larger than the sum of its proper divisors (1).
13430433302347 is an equidigital number, since it uses as much as digits as its factorization.
13430433302347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 653184, while the sum is 40.
Adding to 13430433302347 its reverse (74320333403431), we get a palindrome (87750766705778).
The spelling of 13430433302347 in words is "thirteen trillion, four hundred thirty billion, four hundred thirty-three million, three hundred two thousand, three hundred forty-seven".
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