Base | Representation |
---|---|
bin | 1100001101110000100011… |
… | …0011001100111110001001 |
3 | 1202112221111100201112020112 |
4 | 3003130020303030332021 |
5 | 3230021141123443133 |
6 | 44321520304004105 |
7 | 2554215365405411 |
oct | 303341063147611 |
9 | 52487440645215 |
10 | 13430510374793 |
11 | 4308935a79276 |
12 | 160ab0a900635 |
13 | 765651336c65 |
14 | 34607c329641 |
15 | 1845598c1648 |
hex | c3708cccf89 |
13430510374793 has 2 divisors, whose sum is σ = 13430510374794. Its totient is φ = 13430510374792.
The previous prime is 13430510374781. The next prime is 13430510374889. The reversal of 13430510374793 is 39747301503431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12407604688249 + 1022905686544 = 3522443^2 + 1011388^2 .
It is a cyclic number.
It is not a de Polignac number, because 13430510374793 - 220 = 13430509326217 is a prime.
It is not a weakly prime, because it can be changed into another prime (13430510374733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715255187396 + 6715255187397.
It is an arithmetic number, because the mean of its divisors is an integer number (6715255187397).
Almost surely, 213430510374793 is an apocalyptic number.
It is an amenable number.
13430510374793 is a deficient number, since it is larger than the sum of its proper divisors (1).
13430510374793 is an equidigital number, since it uses as much as digits as its factorization.
13430510374793 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2857680, while the sum is 50.
The spelling of 13430510374793 in words is "thirteen trillion, four hundred thirty billion, five hundred ten million, three hundred seventy-four thousand, seven hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •