13430512242335 has 4 divisors (see below), whose sum is σ = 16116614690808. Its totient is φ = 10744409793864.

The previous prime is 13430512242319. The next prime is 13430512242341. The reversal of 13430512242335 is 53324221503431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13430512242335 - 2⁴ = 13430512242319 is a prime.

It is a super-3 number, since 3×13430512242335³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1343051224229 + ... + 1343051224238.

It is an arithmetic number, because the mean of its divisors is an integer number (4029153672702).

Almost surely, 2^{13430512242335} is an apocalyptic number.

13430512242335 is a deficient number, since it is larger than the sum of its proper divisors (2686102448473).

13430512242335 is an equidigital number, since it uses as much as digits as its factorization.

13430512242335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2686102448472.

The product of its (nonzero) digits is 259200, while the sum is 38.

Adding to 13430512242335 its reverse (53324221503431), we get a palindrome (66754733745766).

The spelling of 13430512242335 in words is "thirteen trillion, four hundred thirty billion, five hundred twelve million, two hundred forty-two thousand, three hundred thirty-five".