Base | Representation |
---|---|
bin | 101000000001101… |
… | …0101110101011011 |
3 | 10110121012011120011 |
4 | 1100003111311123 |
5 | 10222310200042 |
6 | 341134142351 |
7 | 45165522562 |
oct | 12003256533 |
9 | 3417164504 |
10 | 1343053147 |
11 | 62a133787 |
12 | 3159519b7 |
13 | 185330407 |
14 | ca52abd9 |
15 | 7cd96a17 |
hex | 500d5d5b |
1343053147 has 2 divisors, whose sum is σ = 1343053148. Its totient is φ = 1343053146.
The previous prime is 1343053141. The next prime is 1343053157. The reversal of 1343053147 is 7413503431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1343053147 - 215 = 1343020379 is a prime.
It is not a weakly prime, because it can be changed into another prime (1343053141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671526573 + 671526574.
It is an arithmetic number, because the mean of its divisors is an integer number (671526574).
Almost surely, 21343053147 is an apocalyptic number.
1343053147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343053147 is an equidigital number, since it uses as much as digits as its factorization.
1343053147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 31.
The square root of 1343053147 is about 36647.6895178946. The cubic root of 1343053147 is about 1103.3104533569.
Adding to 1343053147 its reverse (7413503431), we get a palindrome (8756556578).
The spelling of 1343053147 in words is "one billion, three hundred forty-three million, fifty-three thousand, one hundred forty-seven".
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