Base | Representation |
---|---|
bin | 1100001101110000101001… |
… | …0010000111010001011011 |
3 | 1202112221120002112120122112 |
4 | 3003130022102013101123 |
5 | 3230021214011131011 |
6 | 44321522553142535 |
7 | 2554216120032011 |
oct | 303341222072133 |
9 | 52487502476575 |
10 | 13430535255131 |
11 | 4308949022235 |
12 | 160ab170baa4b |
13 | 765656538857 |
14 | 3460817648b1 |
15 | 18455bb8858b |
hex | c370a48745b |
13430535255131 has 2 divisors, whose sum is σ = 13430535255132. Its totient is φ = 13430535255130.
The previous prime is 13430535255113. The next prime is 13430535255167. The reversal of 13430535255131 is 13155253503431.
Together with previous prime (13430535255113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13430535255131 is a prime.
It is a super-2 number, since 2×134305352551312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13430535258131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715267627565 + 6715267627566.
It is an arithmetic number, because the mean of its divisors is an integer number (6715267627566).
Almost surely, 213430535255131 is an apocalyptic number.
13430535255131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13430535255131 is an equidigital number, since it uses as much as digits as its factorization.
13430535255131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 405000, while the sum is 41.
Adding to 13430535255131 its reverse (13155253503431), we get a palindrome (26585788758562).
The spelling of 13430535255131 in words is "thirteen trillion, four hundred thirty billion, five hundred thirty-five million, two hundred fifty-five thousand, one hundred thirty-one".
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