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134310535 = 526862107
BaseRepresentation
bin10000000000101…
…10101010000111
3100100201200102021
420000112222013
5233340414120
621154424011
73220422622
oct1000265207
9310650367
10134310535
11698a6547
1238b92007
1321a977b8
1413ba2db9
15bbd0aaa
hex8016a87

134310535 has 4 divisors (see below), whose sum is σ = 161172648. Its totient is φ = 107448424.

The previous prime is 134310529. The next prime is 134310541. The reversal of 134310535 is 535013431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 535013431 = 2918448739.

It is an interprime number because it is at equal distance from previous prime (134310529) and next prime (134310541).

It is a cyclic number.

It is not a de Polignac number, because 134310535 - 25 = 134310503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13431049 + ... + 13431058.

It is an arithmetic number, because the mean of its divisors is an integer number (40293162).

Almost surely, 2134310535 is an apocalyptic number.

134310535 is a deficient number, since it is larger than the sum of its proper divisors (26862113).

134310535 is an equidigital number, since it uses as much as digits as its factorization.

134310535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26862112.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 134310535 is about 11589.2422099117. The cubic root of 134310535 is about 512.1179830135.

Adding to 134310535 its reverse (535013431), we get a palindrome (669323966).

The spelling of 134310535 in words is "one hundred thirty-four million, three hundred ten thousand, five hundred thirty-five".

Divisors: 1 5 26862107 134310535