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134311023223 = 1310331617171
BaseRepresentation
bin111110100010110001…
…1111001001001110111
3110211200100212220201121
41331011203321021313
54200032110220343
6141411315204411
712463231601116
oct1750543711167
9424610786647
10134311023223
1151a63086743
12220445a6707
13c886083550
146701c61c7d
153761573aed
hex1f458f9277

134311023223 has 4 divisors (see below), whose sum is σ = 144642640408. Its totient is φ = 123979406040.

The previous prime is 134311023221. The next prime is 134311023227. The reversal of 134311023223 is 322320113431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134311023223 - 21 = 134311023221 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134311023221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5165808573 + ... + 5165808598.

It is an arithmetic number, because the mean of its divisors is an integer number (36160660102).

Almost surely, 2134311023223 is an apocalyptic number.

134311023223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

134311023223 is a deficient number, since it is larger than the sum of its proper divisors (10331617185).

134311023223 is a wasteful number, since it uses less digits than its factorization.

134311023223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10331617184.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 134311023223 its reverse (322320113431), we get a palindrome (456631136654).

The spelling of 134311023223 in words is "one hundred thirty-four billion, three hundred eleven million, twenty-three thousand, two hundred twenty-three".

Divisors: 1 13 10331617171 134311023223