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134312262051 = 3114070068547
BaseRepresentation
bin111110100010110100…
…0100111100110100011
3110211200110012212002010
41331011220213212203
54200032414341201
6141411401524003
712463245250632
oct1750550474643
9424613185063
10134312262051
1151a63852470
1222044aa3603
13c8863c8396
1467020a5519
15376171abd6
hex1f45a279a3

134312262051 has 8 divisors (see below), whose sum is σ = 195363290304. Its totient is φ = 81401370920.

The previous prime is 134312262047. The next prime is 134312262059. The reversal of 134312262051 is 150262213431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 134312262051 - 22 = 134312262047 is a prime.

It is not an unprimeable number, because it can be changed into a prime (134312262059) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2035034241 + ... + 2035034306.

It is an arithmetic number, because the mean of its divisors is an integer number (24420411288).

Almost surely, 2134312262051 is an apocalyptic number.

134312262051 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

134312262051 is a deficient number, since it is larger than the sum of its proper divisors (61051028253).

134312262051 is a wasteful number, since it uses less digits than its factorization.

134312262051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4070068561.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 134312262051 its reverse (150262213431), we get a palindrome (284574475482).

The spelling of 134312262051 in words is "one hundred thirty-four billion, three hundred twelve million, two hundred sixty-two thousand, fifty-one".

Divisors: 1 3 11 33 4070068547 12210205641 44770754017 134312262051