Base | Representation |
---|---|
bin | 111110100010110100… |
… | …0100111100110100011 |
3 | 110211200110012212002010 |
4 | 1331011220213212203 |
5 | 4200032414341201 |
6 | 141411401524003 |
7 | 12463245250632 |
oct | 1750550474643 |
9 | 424613185063 |
10 | 134312262051 |
11 | 51a63852470 |
12 | 22044aa3603 |
13 | c8863c8396 |
14 | 67020a5519 |
15 | 376171abd6 |
hex | 1f45a279a3 |
134312262051 has 8 divisors (see below), whose sum is σ = 195363290304. Its totient is φ = 81401370920.
The previous prime is 134312262047. The next prime is 134312262059. The reversal of 134312262051 is 150262213431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 134312262051 - 22 = 134312262047 is a prime.
It is not an unprimeable number, because it can be changed into a prime (134312262059) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2035034241 + ... + 2035034306.
It is an arithmetic number, because the mean of its divisors is an integer number (24420411288).
Almost surely, 2134312262051 is an apocalyptic number.
134312262051 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
134312262051 is a deficient number, since it is larger than the sum of its proper divisors (61051028253).
134312262051 is a wasteful number, since it uses less digits than its factorization.
134312262051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4070068561.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 134312262051 its reverse (150262213431), we get a palindrome (284574475482).
The spelling of 134312262051 in words is "one hundred thirty-four billion, three hundred twelve million, two hundred sixty-two thousand, fifty-one".
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