Base | Representation |
---|---|
bin | 111110100010110100… |
… | …0100111100110011111 |
3 | 110211200110012212001222 |
4 | 1331011220213212133 |
5 | 4200032414341142 |
6 | 141411401523555 |
7 | 12463245250625 |
oct | 1750550474637 |
9 | 424613185058 |
10 | 134312262047 |
11 | 51a63852467 |
12 | 22044aa35bb |
13 | c8863c8392 |
14 | 67020a5515 |
15 | 376171abd2 |
hex | 1f45a2799f |
134312262047 has 2 divisors, whose sum is σ = 134312262048. Its totient is φ = 134312262046.
The previous prime is 134312262043. The next prime is 134312262059. The reversal of 134312262047 is 740262213431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134312262047 - 22 = 134312262043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134312261998 and 134312262016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134312262043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67156131023 + 67156131024.
It is an arithmetic number, because the mean of its divisors is an integer number (67156131024).
Almost surely, 2134312262047 is an apocalyptic number.
134312262047 is a deficient number, since it is larger than the sum of its proper divisors (1).
134312262047 is an equidigital number, since it uses as much as digits as its factorization.
134312262047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 134312262047 its reverse (740262213431), we get a palindrome (874574475478).
The spelling of 134312262047 in words is "one hundred thirty-four billion, three hundred twelve million, two hundred sixty-two thousand, forty-seven".
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