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134312696213401 is a prime number
BaseRepresentation
bin11110100010100000011100…
…100010111110111110011001
3122121120011112201210111001001
4132202200130202332332121
5120101034400212312101
61153354222325025001
740201525551524536
oct3642403442767631
9577504481714031
10134312696213401
1139883770540142
121309284a255161
1359c382c658a14
142524aaa8cbd8d
15107dbac658901
hex7a281c8bef99

134312696213401 has 2 divisors, whose sum is σ = 134312696213402. Its totient is φ = 134312696213400.

The previous prime is 134312696213393. The next prime is 134312696213407. The reversal of 134312696213401 is 104312696213431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72452033039376 + 61860663174025 = 8511876^2 + 7865155^2 .

It is a cyclic number.

It is not a de Polignac number, because 134312696213401 - 23 = 134312696213393 is a prime.

It is a super-2 number, since 2×1343126962134012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134312696213407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67156348106700 + 67156348106701.

It is an arithmetic number, because the mean of its divisors is an integer number (67156348106701).

Almost surely, 2134312696213401 is an apocalyptic number.

It is an amenable number.

134312696213401 is a deficient number, since it is larger than the sum of its proper divisors (1).

134312696213401 is an equidigital number, since it uses as much as digits as its factorization.

134312696213401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 559872, while the sum is 46.

The spelling of 134312696213401 in words is "one hundred thirty-four trillion, three hundred twelve billion, six hundred ninety-six million, two hundred thirteen thousand, four hundred one".