Base | Representation |
---|---|
bin | 10011100010111110010… |
… | …001110011011001000101 |
3 | 11202102002110102101002120 |
4 | 103202332101303121011 |
5 | 134001404331244331 |
6 | 2505022344000153 |
7 | 166021203521013 |
oct | 23427621633105 |
9 | 4672073371076 |
10 | 1343222134341 |
11 | 47872597147a |
12 | 1983aa460059 |
13 | 99885898269 |
14 | 49025a638b3 |
15 | 24e1872d796 |
hex | 138be473645 |
1343222134341 has 4 divisors (see below), whose sum is σ = 1790962845792. Its totient is φ = 895481422892.
The previous prime is 1343222134301. The next prime is 1343222134363. The reversal of 1343222134341 is 1434312223431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1343222134341 - 210 = 1343222133317 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1343222134301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223870355721 + ... + 223870355726.
It is an arithmetic number, because the mean of its divisors is an integer number (447740711448).
Almost surely, 21343222134341 is an apocalyptic number.
It is an amenable number.
1343222134341 is a deficient number, since it is larger than the sum of its proper divisors (447740711451).
1343222134341 is an equidigital number, since it uses as much as digits as its factorization.
1343222134341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 447740711450.
The product of its digits is 41472, while the sum is 33.
Adding to 1343222134341 its reverse (1434312223431), we get a palindrome (2777534357772).
The spelling of 1343222134341 in words is "one trillion, three hundred forty-three billion, two hundred twenty-two million, one hundred thirty-four thousand, three hundred forty-one".
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