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1343222133317 is a prime number
BaseRepresentation
bin10011100010111110010…
…001110011001001000101
311202102002110102022200122
4103202332101303021011
5134001404331231232
62505022343551325
7166021203515021
oct23427621631105
94672073368618
101343222133317
11478725970729
121983aa45b545
139988589795c
1449025a63381
1524e1872d312
hex138be473245

1343222133317 has 2 divisors, whose sum is σ = 1343222133318. Its totient is φ = 1343222133316.

The previous prime is 1343222133287. The next prime is 1343222133359. The reversal of 1343222133317 is 7133312223431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1284246496516 + 58975636801 = 1133246^2 + 242849^2 .

It is an emirp because it is prime and its reverse (7133312223431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1343222133317 - 214 = 1343222116933 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1343222130317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671611066658 + 671611066659.

It is an arithmetic number, because the mean of its divisors is an integer number (671611066659).

Almost surely, 21343222133317 is an apocalyptic number.

It is an amenable number.

1343222133317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343222133317 is an equidigital number, since it uses as much as digits as its factorization.

1343222133317 is an evil number, because the sum of its binary digits is even.

The product of its digits is 54432, while the sum is 35.

Adding to 1343222133317 its reverse (7133312223431), we get a palindrome (8476534356748).

The spelling of 1343222133317 in words is "one trillion, three hundred forty-three billion, two hundred twenty-two million, one hundred thirty-three thousand, three hundred seventeen".